18v^2=45v

Solution for 18v^2=45v equation:

18v^2=45v

We move all terms to the left:

18v^2-(45v)=0

a = 18; b = -45; c = 0;
Δ = b2-4ac
Δ = -452-4·18·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-45}{2*18}=\frac{0}{36}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+45}{2*18}=\frac{90}{36}
=2+1/2
$